(z^2)(z^2+3z+2)=y

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Solution for (z^2)(z^2+3z+2)=y equation: 


Simplifying
(z2)(z2 + 3z + 2) = y

Reorder the terms:
z2(2 + 3z + z2) = y
(2 * z2 + 3z * z2 + z2 * z2) = y
(2z2 + 3z3 + z4) = y

Solving
2z2 + 3z3 + z4 = y

Solving for variable 'z'.

Reorder the terms:
-1y + 2z2 + 3z3 + z4 = y + -1y

Combine like terms: y + -1y = 0
-1y + 2z2 + 3z3 + z4 = 0

The solution to this equation could not be determined.

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